Question 416857
The difference between the squares of two 
consecutive even numbers is twice the sum of the numbers.
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1st: 2x
2nd: 2x+2
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(2x)^2-(2x+2)^2 = 2(2x+2x+2)
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4x^2-[4x^2+8x+4] = 8x+4
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-8x-4 = 8x+4
Didn't work.
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You have to take the square of the larger - the square of the smaller:
(2x+2)^2-(2x)^2 = 2(2x+2x+2)
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4x^2+8x+4-4x^2 = 8x+4
8x+4 = 8x+4
That works.
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Cheers,
Stan H.
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