Question 416749
Use quadratic form to solve 4x^2-3x+2=0

a=4 , b = -3  , c = 2    .

b^2-4ac=-23

{{{x=(-b+-sqrt(b^2-4ac))/(2a)}}}


{{{x1=(3+sqrt(-23))/(8)}}}

x1=0.375 + 0.59947894 i
...
{{{x2=(-b-sqrt(b^2-4ac))/(2a)}}}

{{{x1=(3-sqrt(-23))/(8)}}}
x2=0.375 - 0.5994789404140899i

complex roots