<PRE><B>Question 416693</B>
a company manufactures a television which is found to have a 10% probability of being defective in some way. a sample of 4 televisions is taken.
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Binomial Problem with n = 4 and p = 0.1
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1) what is the probability that exactly 1 television will be defective?
P(x=1) = 4C1(0.1)*(0.9)^3 = 0.2916
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2) what is the mean of this distribution?
u = np = 4*0.1 = 0.4
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3) what is the standard deviation of this distribution?
std = sqrt[npq] = sqrt[0.4*0.9] = 0.6
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Cheers,
Stan H.
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