Question 416582

{{{ 2x^2 +7x +3 }}}

there are many methods to solve this problem...
I would use the method of factorization

I would find two numbers whose sum is 7 and product is 6

such two numbers are  1 and 6 (coz, 1+6 = 7 and 1*6 = 6)

Now i would split the middle term with these numbers...


{{{ 2x^2 +1x + 6x +3 }}}=0

{{{ (2x^2 +1x) + (6x +3) }}}=0

{{{ x(2x +1) + 3(2x +1) }}} = 0

{{{ (2x +1)(x + 3)}}} = 0


==>  2x + 1 = 0          or   x + 3 = 0


==>  2x = -1              or  x = -3

===> {{{x = -1/2}}}  or {{{ x = -3 }}}