Question 44278
{{{m^3-27 =(m-3)^3}}}
{{{m^3-27 =(m-3)(m-3)(m-3)}}}

For the remaining problems, you need to simplify and rearrange the expressions to give a quadratic equation of the form {{{ax^2+bx+c=0}}}which can be solved using the solver {{{x = (-b +- sqrt( b^2-4ac ))/(2a) }}}.

For the first of these problems submitted you should divide both sides by x to give: {{{x^2-x-20=0}}}
Now use {{{x = (-b +- sqrt( b^2-4ac ))/(2a) }}}
where 
a=1
b=-1
c=20
To get {{{x = (1 +- sqrt( 1-80 ))/2 }}}
{{{x = (1 +- sqrt( -79 ))/2 }}}
{{{x = (1 +- (sqrt( 79 ))i)/2 }}}
where "i" denotes the imaginary number {{{i=sqrt(-1)}}}.

The second and third of these problems require simplifying and rearranging to give quadratic equations of the form {{{ax^2+bx+c=0}}} which can be fairly easily solved.

The second one should be rearranged to give {{{5x^2+3x-2=0}}}, then use the quadratic solver already mentioned to obtain {{{x=(-3 +- 7)/10}}}.



I hope this helps.
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk