Question 416476
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Hi
Let x and (x+2) represent the two consecutive 'positive' even integers 
Question states***
 x^2 + (x+2)^2 = 164
Solving for x
 x^2 + x^2 + 4x + 4 = 164
   2x^2 + 4x - 160 = 0
    x^2 + 2x - 80 = 0
factoring
  (x+10)(x-8)= 0  Note:SUM of the inner product(10x) and the outer product(-8x)=2x  
  (x+10)=0  x = -10  Tossing out negative solution for 'positive integer'
  (x-8)= 0  x = 8   the two consecutive 'positive' even integers are 8,10

CHECKING our Answer***
  64 + 100 = 164