Question 416427
Two cards are drawn without replacement from an ordinary deck of 52
playing cards. What is the probability that the second card is a spade if
the first card was not a spade?
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P(spade|not spade) = P(spade and not spade)/P(not spade)
[(1/4)(39/51)]/[39/52] = 13/51
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c is correct
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Cheers,
Stan H.
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a)1/4
b)4/17
c)13/51
d)4/51 
Here is my answer : c