Question 44258
{{{(w-1/4)^2=(w-1/4)(w-1/4)}}}
Use FOIL (first, outers, inners, lasts) to add the products of the expressions in the brackets.
If you had to multiply (a+b) by (c+d), using FOIL you would get:
{{{(a+b)(c+d)=ab+ad+bc+cd}}}

So:
{{{(w-1/4)(w-1/4)=w^2-w/4-w/4+1/16}}}
{{{(w-1/4)(w-1/4)=w^2-2(w/4)+1/16}}}
{{{(w-1/4)(w-1/4)=w^2-2w/2+1/16}}}

I hope this helps
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk