Question 416392
Solution: Three consecutive ood integers are: x, x+2, x+4. Since their sum is 141 we write the equation: x+x+2+x+4=141, 3x+6=141, 3x=135, x=45. The first ood number is 45, the second 45+2=47 and the third 47+2=49.
Proof: 45+47+49=141.