Question 416392
Let the integers be n, n+2, n+4, since they are consecutive ODD integers
We have {{{n + (n+2) + (n+4) = 141}}}
Solve for n: {{{3n + 6 = 141}}} -> {{{3n = 135 -> n = 45}}}
Thus, the integers are: 45,47,49
Check: 45+47+49=141