Question 416314
This would seem to be a physics problem.  
The period, T, of a pendulum (for small oscillations) is given by T = {{{ 2*pi*sqrt(L/g)}}}, where L=length, g=acceleration due to gravity.
We assume g=32 ft/s^2, and note the problem only asks for the time for half of a period.
Inserting the values for L and g in the formula, we have 
{{{T = 2*pi*sqrt( 32/pi^2/32 )}}}
This reduces to {{{T=2*pi/pi = 2}}}
The time required to swing from one side to the other is 1/2 T.
Answer: 1 second.