Question 416213
one leg = x
other leg = 2x-4
hypotenuse = 10

x^2+(2x-4)^2=100
x^2+4x^2-16x+16=100
5x^2-16x-84=0
5x^2-30x+14x-84=0
5x(x-6)+14(x-6)=0
(x-6)(5x+14)=0
x=6 one leg
other leg = 2x-4====> 12-4=8