<PRE><B>Question 415788</B>
The rectangular swimming pool measures 40 feet by 60 feet and is surrounded by a
 path of uniform width around the four edges..
The perimeter of the rectangle formed by the pool and the surrounding path is 248 feet.
 Determine the width of the path.
:
Let x = the width of the path
:
The surrounding path will add 2x to the pool dimensions, therefore
over all dimensions: (2x+40) by (2x+60)
:
the overall perimeter
2(2x+40) + 2(2x+60) = 248 
Simplify divide by 2, results
(2x + 40) + (2x + 60) = 124
combine like terms
2x + 2x + 40 + 60 = 124
4x + 100 = 124
4x = 124 - 100
4x = 24
x = {{{24/4}}}
x = 6 ft is the width of the path
:
:
Check this by finding the perimeter with these values; 2x = 12 ft
2(12+40) + 2(12+60)
2(52 + 2(72)
104 + 144 = 248; confirms our solution of x=6 ft</PRE>