Question 416045
If the graph of f is decreasing on [0,infinity), then 
what can be said about the graph of y = f(-x) + 1? 
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It is increasing on (-inf,0] but is not symmetric
to the original "f".
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the graph of y = - f(x) - 1?
It is decreasing on [0,+inf); it is not symmetric to "f".
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Cheers,
Stan H.