Question 415948
{{{f(x)=root(3,2x+1)}}}



{{{y=root(3,2x+1)}}}



{{{x=root(3,2y+1)}}}



{{{x^3=2y+1}}}



{{{x^3-1=2y}}}



{{{(x^3-1)/2=y}}}



{{{y=(x^3-1)/2}}}



So the inverse function is *[Tex \LARGE f^{-1}(x)=\frac{x^3-1}{2}]



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