Question 415873
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Hi
Let x and (x+5in) represent the width and length respectively
Question states***
  2(x+5in) + 2x = 30in
Solving for x
   4x = 20
    x = 5in, the width.  The length is 10in   (5in + 5in)
CHECKING our Answer***
 2*10in + 2*5in = 20in + 10in = 30in 
<img src="http://upload.wikimedia.org/wikipedia/commons/thumb/d/da/PerimeterRectangle.svg/200px-PerimeterRectangle.svg.png">