Question 415857
We have two consecutive ODD integers, n and n+2.
Difference of the squares:
{{{n^2 - (n+2)^2 = 40}}}
Solving for n gives {{{n^2 - n^2 - 4n - 4 = 40}}} -> {{{-4(n+1) = 40}}}
This gives n = -11.  Therefore the other integer, n+2, is -9.
Check:
(-11)^2 - (-9)^2 = 40
121 - 81 = 40