Question 415782
{{{(a^5bc^-8)^-9=a^(5*(-9))b^(1*(-9))c^(-8*(-9))=a^(-45)b^(-9)c^(72)=(1/a^45)(1/b^9)(c^72)=(c^72)/(a^45*b^9)}}}



So {{{(a^5bc^-8)^-9=(c^72)/(a^45*b^9)}}}



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