Question 415857
The difference of the squares of two consecutive negative odd integers is 40. Find the numbers.

I tried to set it up like this: n=1st integer n-1=2nd integer
n2-(n-1)2=40 (the 2's are squares, but I can't do it on my keyboard)
but then I get stuck.
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The 2nd number should be n-2, since both numbers are odd.
{{{n^2 - (n-2)^2 = 40}}}
{{{n^2 - (n^2 - 4n + 4) = 40}}}
4n - 4 = 40
4n = 44
n = 11
--> 11 & 9
or -11 & -9
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PS  Use n^2 for squared, the shifted 6.