Question 415781
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Hi
-2log[base 4]x=log[base 4]8
*[tex \LARGE\ \ nlog_bx = log_b(x^n) ]
log[base 4](x^-2) = log[base 4]8
      x^-2 = 8
     1/x^2 = 8       |Multiplying each side by x^2
        1 = 8x^2     |Dividing both sides by 8
        1/8 = x^2
 {{{x = sqrt(1/8) = 1/(2sqrt(2)) = sqrt(2)/(2sqrt(2)*sqrt(2)) = sqrt(2)/4}}}