Question 415786
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Hi
 log(x^2+3x+2)-2log(x+1)
*[tex \LARGE\ \ nlog_bx = log_b(x^n) ]
log(x^2+3x+2)-log(x+1)^2
*[tex \LARGE\ \ log_bx - log_by = log_b(x/y) ]
log(x^2+3x+2)/(x+1)^2    |This would be as a single logarithm
simplify as is customary for Your work:
log(x+1)(x+2)/(x+1)^2
log (x+2)/(x+1)