Question 43904
y=x^2+4x+5 
Write in vertex form by completing the square, as follows:
x^2+4x=y-5
x^2+4x+4=y-5+4
(x+2)^2=y-1

Please include:
a) opens up, down, right or left
Has the form y=+x^2 s]o it opens up.
b)vertex
vertex = (-2,1)
c) axis of symmetry
vertical line through the vertex: x=-2
d) X-intercept
Let y=0 and solve for x in original equation:
x^2+4x+5=0
x=[-4+sqrt(16-20)]/2; discriminant is negative so no x intercepts.
e) y-intercept
Let x=0 in original equation: y=5

f)graph
*[invoke quadratic "x",1,4,5]
Cheers,
stan H.