Question 415755
2log[base 3](x+4)-log[base 3]9=2
-----
2log3(x+4) - log3(9) = 2
---
log3[(x+4)^2/9] = 2
----
(x+4)^2/9 = 3^2
(x+4)^2 = 81
---
x^2+8x+16-81 = 0
---
x^2 + 8x - 55 = 0
---
x  = [-8 +- sqrt(64-4*-55)]/2
----
x = [-8 +- sqrt(284)]/2
---
x = [-8 +- 2sqrt(71)]/2
---
x = -4+sqrt(71) or x = -4-sqrt(71)
==================
Cheers,
Stan H.
============