Question 415677
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Hi
four consecutive integers 
Letting x,(x+1)(x+2)(x+3) represent them.  Their sum is 4x+6
Question states***
 51 <4x + 6 <65   OR    11 < x < 15   
12,13,14,15  OR 14,15,16,17 are four consecutive integers whose sum is between 51 and 65
CHECKING our Answer***
  12+13+14+15 = 54
  14+15+16+17  = 62