Question 415642
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Hi
The perimeter of a rectangle is 246 inches. The length exceeds the width by 77inches
Let x and (x+77in) represent the width and length respectively:
     P =  2(x+77in)+ 2x = 246in 
            4x = 92in
             x = 18in, the width
<img src="http://upload.wikimedia.org/wikipedia/commons/thumb/d/da/PerimeterRectangle.svg/200px-PerimeterRectangle.svg.png">