Question 44188
Solve ∆ABC if C=90 degrees, B=20 degrees, and b=10. Round measures of sides to the nearest tenth and measures of angles to the nearest degree. 

Angle A = 90-20=70 degrees

Using the Law of Sines:
a/sinA = b/SinB
a/sin70 = 10/sin20
a/0.9397=10/0.3420
a=9.397/0.3420
a=27.4767..

c=sqrt(a^2+b^2)
c=sqrt(27.47^2+10^2)
c=29.238
Cheers,
Stan H.