Question 415544
We have {{{t[n] = 2t[n-1] + 3}}} and the initial condition {{{t[1] = 2}}}. To find {{{t[2]}}}, just replace n with 2 in the first equation, i.e.


{{{t[2] = 2t[1] + 3 = 2(2) + 3 = 7}}} (since we already have {{{t[1] = 2}}})


Repeat the same process to find {{{t[3]}}} through {{{t[5]}}}.