Question 415503
{{{sqrt(x+7)=x-5}}}
Take the square on both sides
(x+7)=(x-5)^2
x+7 = x^2-10x+25
x^2-10x-x+25-7=0
x^2-11x+18=0
x^2-9x-2x+18=0
x(x-9)-2(x-9)=0
(x-9)(x-2)=0
x=9 OR x=2