Question 415311
Solve the following equation.
36x^3 - x = 0
:
Factor out x
x(36x^2 - 1) = 0
:
Factor as the difference of squares
x(6x+1)(6x-1) = 0
:
Three solutions
x = 0
and
6x = -1
x = {{{-1/6}}}
and 
6x = 1
x = {{{1/6}}}