Question 44173
{{{9x^4 - 24x^3 + 16x^2 = 0}}}
divide both sides by {{{x^2}}}
 {{{9x^2 - 24x + 16 = 0}}}
Now you have a quadratic that can be solved using {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
Note that because you have divided everything by {{{x^2}}} every solution you obtain will have an opposite of that solution attatched to it.
For example, if you obtained x=1 and x=2 from the quadratic, solutions x=-1 and x=-2 would also exist these are called "congugate" roots. All the solutions would be x=-2,-1,1,2.


I hope this helps 
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk