Question 44171
{{{9x^2-6x+37=0}}}
Use the quadratic solver: {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
where
a = 9
b = -6
c = 37
Now:
{{{x = (6 +- sqrt( 6^2-4*9*37 ))/(2*9) }}}
{{{x = (6 +- sqrt( 36-1332 ))/18 }}}
{{{x = (6 +- sqrt( -1296 ))/18 }}}
{{{x = (6 +- 36sqrt( -1 ))/18 }}}
{{{x = 1/3 +- 2i }}}
where "i" represents the imaginary number {{{i=sqrt(-1)}}}

I hope this helps 
P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk