Question 415108
f(x)=-2x^3-3x^2+5x-4. 
Use the intermediate value theorum to show that f has a zero between 0 and -1.
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f(-1) = -2(-1)^3-3(-1)^2+5(-1)-4 = -2(-1)-3(1)-5-4 < 0
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f(0) = -4 
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Note: It doesn't have a zero between -1 and 0
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Cheers,
Stan H.