Question 415126

Let integers are x and x+2

x(x+2) = 168

=> x^2 +2x -168 = 0

=> x^2 +14x -12x  -168 = 0

=> x(x +14) -12(X+ 14) = 0

=> (x-12)(x+14) = 0 


so, x = 12

numbers are 12 and 14