Question 415066
patrick drove 5 hours to attend a meeting. on the return trip, his speed was 10 miles per hour less and took 6 hours. what was his speed each way? how far did he drive to the meeting?
Going out speed	xmph		
returning speed =10mph 	slower	
returning speed	x-10	
returning time =	6 hours		
going out time=	5hours		
					
Distance = same					

5x=6(x-10)		
5x=6x-60				
5x-6x=-60			
-1x=-60						
/-1									
x=60mph						
										
Returning speed=	50 mph