Question 415011
graph and find the vertex, y-intercept and line of symmetry of the following equation: y=(x-3)^2+4.
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Vertex: (3,4)
y-int: (0,13)
line of sym: x = 3
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{{{graph(400,300,-10,10,-10,10,(x-3)^2+4)}}}
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Cheers,
Stan H.
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