Question 414746
The total capacity of the pool is 1000 cubic meters. the filling of the pool started on Thursday morning at 6 o’clock.
 On Friday morning at 9 o’clock when the pool was being filled, the pump for removal of water was started by mistake.
 Starting from this point onwards, water was both added and removed from the pool.
The pool became empty on Monday evening at 6 o’clock pm (18:00).
 It can be assumed that the rate at which the water was added and removed were both constant.
:
I think you have to know the pumping rate of one of the pumps so solve this.
You can write an equation: 
Let x = filling pump rate
Let y = emptying pump rate
:
From Thursday 6 am to Monday at 6 pm = 108  is x pumping time
The emptying pump ran 27 hrs less; 81 = y pumping time
:
108x - 81y = 0
81y = 108x
y = {{{108/81}}}x
y = 1.33x
:
If you have a value for either x or y, you can  answer these questions
.
a) When would the pool have been full if the pump to remove the water had not been started? 
State in your answer the day of the week and the time of the day with the
accuracy of one hour.
 You can solve the problem graphically or mathematically.




b) How many cubic meters of water does the removing pump get rid of in 24 hours?