<PRE><B>Question 414895</B>
The sides of one square have length 3 m more than the sides of a second square. If the area of the larger square is subtracted from 4 times the area of the smaller square, the result is 36 m^2. What are the lengths of the sides of each square?

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1st Square DATA:
Side = x
Area = x^2
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2nd Square DATA:
side = x+3
Area = (x+3)^2
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Equation:
 4*smaller area - larger area = 36 m^2
4x^2 - (x+3)^2  = 36
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4x^2-[x^2+6x+9] - 36 = 0
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4x^-x^2-6x-9-36 = 0
3x^2-6x-45 = 0
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x^2-2x-15 = 0
(x-7)(x+2) = 0
Positive solution:
x = 7m (side of smaller square)
x+3 = 10m (side of larger square)
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Cheers,
Stan H.
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