Question 414816


given:

the perimeter {{{P}}} of a rectangle is {{{144m}}}. 

{{{P=144m}}}

the length {{{a}}} is {{{3m}}} more then {{{twice}}} the WIDTH {{{b}}}

{{{a=2b+3m}}}

-------------------

find {{{b}}}

{{{P = 2a+2b}}}

{{{144m =2(2b+3m)+2b}}}

{{{144m =4b+6m+2b}}}

{{{144m-6m = 6b}}}

{{{138m = 6b}}}

{{{b = 138m/6}}}

{{{b = 23m}}}.......find {{{a}}}


{{{a=2b+3m}}}


{{{a=2(23m)+3m}}}

{{{a=46m+3m}}}

{{{a=49m}}}



check:



{{{144m =2a+2b}}}

{{{144m =2*49m+2*23m}}}

{{{144m =98m+46m}}}

{{{144m =144}}}