Question 414745
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Hi
Let x and (x+1) represent the two consecutive integers
Question states***
 [x + (x+1)]^2 = 81
Solving for x
 (2x+1)^2 = 81
 4x^2 + 4x + 1 = 81
 4x^2 + 4x -80 = 0
 x^2 + x -20 = 0
factoring
(x+5)(x-4) = 0
(x+5)= 0   x = -5    the two consecutive integers are -5,-4
or
(x-4) = 0  x = 4     the two consecutive integers are 4,5
 
CHECKING our Answer***
 (-9)^2 = 81
 (9)^2= 81