Question 414694
Let 1st number=x
2nd number=x+1
{{{x(x+1)=812}}}
{{{x^2+x=812}}}
{{{x^2+x-812=0}}}
Lets use the quadratic equation to factor the equation 
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
 a=1 b=1 c=-812
{{{x = (1 +- sqrt( 1^2-4*1*-812 ))/(2*1) }}}
{{{x = (1 +- sqrt( 1-(-812)4 ))/(2) }}}
{{{x = (1 + sqrt(3249 ))/(2) }}} {{{x = (1 - sqrt(3249 ))/(2) }}}
{{{x = (1 + 57)/(2) }}} {{{x = (1 - 57)/(2) }}} 
{{{x = (58)/(2) }}} {{{x = (-56)/(2) }}} 
{{{x = 29 }}} {{{x = -28 }}} 
The first number is -28 and second number is 29