Question 414694
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Hi
2 consecutive 2-digit numbers
Let x and (x+1) represent the numbers
Question states***
  x(x+1) = 812
Solving for x
 x^2 + x - 812 = 0
factoring
(x+29)(x-28)= 0
(x+29)= 0  x = -29     The 2 consecutive 2-digit numbers are -29,-28
(x-28)= 0  x = 28      The 2 consecutive 2-digit numbers are 28,29