Question 414527
What you missed is the factoring of the equation. In order to
factor it, you need to find the roots. the roots are where the 
graph of the equation intersects the x-axis. That is also
where {{{y = 0}}}, so I can say {{{y = -2h^2-28h-98}}}
Now set {{{y = 0}}}
{{{-2h^2-28h-98 = 0}}}
Divide through by {{{-2}}}
{{{h^2 + 14h + 49 = 0}}}
One way to factor this is with the quadratic formula
{{{h = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
Use this formula when the equation is in the form
{{{ax^2 + b*x + c = 0}}}
{{{a = 1}}}
{{{b = 14}}}
{{{c = 49}}}
Plug in these values:
{{{h = (-14 +- sqrt( 14^2-4*1*49 ))/(2*1) }}} 
{{{h = (-14 +- sqrt( 196 - 196 )) / 2 }}} 
{{{h = (-14 + 0) / 2}}}
{{{h = -7}}}
and also
{{{h = (-14 - 0) / 2}}}
{{{h = -7}}}
In this case you have a double root, both are {{{h = -7}}}
I can write them as:
{{{h + 7 = 0}}}
{{{h + 7 = 0}}}
and
{{{(h + 7)*(h + 7) = 0}}}
Multiplying out,
{{{h^2 + 14h + 49 = 0}}}
So, I have found the 2 factors.
The graph of the equation is:
{{{ graph( 400, 400, -12, 2, -2, 10, x^2 + 14x + 49) }}}