Question 414463
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You got to:


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ 4\ \cdot\ 3\ -\ w\ =\ 0\ +\ w^2]


which is almost correct:


Where you should have gotten was:


*[tex \LARGE\ \ \ \ \ \ \ \ \ \  4(3\ -\ w)\ =\ w^2]


Then


*[tex \LARGE\ \ \ \ \ \ \ \ \ \  12\ -\ 4w\ -\ w^2\ =\ 0]


Then


*[tex \LARGE\ \ \ \ \ \ \ \ \ \ w^2\ +\ 4w\ -\ 12\ =\ 0]


Then factor.  Hint 6 + (-2) = 4 and 6 * (-2) = -12



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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