<PRE><B>Question 414468</B>
please help me find the roots, lines of symmetry, and vertex for 
y=-x^2+5x-4
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-x^2+5x+? = y+4+?
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Complete the square on the x-terms:
-(x^2-5+(5/2)^2) = y+4-(5/2)^2
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Factor:
-(x-(5/2))^2 = y + 16/4 - (25/4)
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-(x-(5/2))^2 = y -9/4
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Symmetry line : x = 5/2
Vertex: (5/2 , (9/4))
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Roots of y = -x^2+5x-4
Solve -x^2+5x-4 = 0
x^2-5x+4 = 0
(x-4)(x-1) = 0
x = 1 or x = 4
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Cheers,
Stan H.
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