Question 414240
A man is 10 years older than his son.
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What??? The man became a father at age 10?????

Surely you miscopied the problem.
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In ten years, he will be twice as old as his son will then be.
How old is each.
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If that were the bizarre case, then

son's age now = x
father's age now = x + 10

son's age in 10 years = x + 10
father's age in 10 years = (x + 10) + 10 or x + 10 + 10 or x + 20

So 

x + 20 = 2(x + 10)

x + 20 = 2x + 20

    -x = 0

     x = 0

son's age now = x = 0
father's age now = x + 10 = 0 + 10 = 10

So the 10-year old boy just became a father, for the baby is
0 years old (just born).  And in ten years the 10-year-old boy 
father will be 20 years old and the son will be 10.

That works, but surely the problem is botched.

Edwin</pre>