Question 414294
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Hi
If y varies inversely as the square of  x  OR y = k/x^2
y = 9  when x = 2        9 = k/4   k = 36
find  the value of x when y = 4
 y = 36/x^2
 4 = 36/x^2
 x^2 = 9
  x = ± 3