Question 414239
Long division:
<pre>
       x^3 + 3x + 10
       ____________________________________
x^2-3 /x^5 + 0x^4 + 0x^3 + 10x^2 + 29x + 20  <-- make sure all powers are here
       x^5        - 3x^3                     <-- subtract
      -------------------
                    3x^3 + 10x^2 + 29x 
                    3x^3         -  9x       <-- line up like terms
                   -------------------
                          10x^2  + 38x + 20
                          10x^2        - 30
                         ------------------
                                   36x + 50  <-- remainder
</pre>
So
{{{(x^5 + 0x^4 + 0x^3 + 10x^2 + 29x + 20)/(x^2-3) = x^3 + 3x + 10 + (36+50)/(x^2-3)}}}