Question 414116
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Hi
Solving:  That is, finding the values of x where the graph crosses the x-axis
x^2=16
x = ± 4    |Taking the square root of both sides of the Equation
{{{drawing(300,300,   -20,20,-20,20,  grid(1),
circle(4, 0,0.5),
circle(-4, 0,0.5),
graph( 300, 300, -20,20,-20,20, 0,x^2 -16))}}}