Question 414079
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Hi
*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]

*[tex \LARGE \ \ \ \ \ \ \ \ \ \ log_x(9) \ = \ -2 \ \ \Rightarrow\ \] {{{x^(-2) = 9}}}

   1/x^2 = 9
     1/9 = x^2
     1/3 = x