Question 413887
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Hi
Identify the maximum or minimum (vertex), zeros, and axis of symmetry lin
Using the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
 y = x^2-4       |Vertex is Pt(0,-4)& a Minimum as Parbola opens upward (a> 0)    x = 0, the line of symmetry
 0 = x^2-4     x = ± 2
{{{drawing(300,300,   -10,10,-10,10, blue(line(0,10,0,-10)),   grid(1),
circle(0, -4,0.4),
circle(2,0,0.4),
circle(-2,0,0.4),
graph( 300, 300, -10,10,-10,10,0,  x^2-4  ))}}}